3y^2+35y+22=0

Solution for 3y^2+35y+22=0 equation:

3y^2+35y+22=0

a = 3; b = 35; c = +22;
Δ = b2-4ac
Δ = 352-4·3·22
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-31}{2*3}=\frac{-66}{6}
=-11
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+31}{2*3}=\frac{-4}{6}
=-2/3
$